Question

Calculate the weight of Na2CO3 present in 100 ml of 0.5N solution

Answer 1

Answer:

Explanation: molarity = normality *n-factor and n-factor is 2 so

Molarity will be 2*0.5=1

Molarity*molar mass* volume= weight

1*105*100/1000=10.5gm

Answer 2

Answer:

Explanation: molarity = normality *n-factor and n-factor is 2 so

Molarity will be 2*0.5=1

Molarity*molar mass* volume= weight

1*105*100/1000=10.5gm

Explanation:

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