Calculate the weight of Na2CO3 present in 100 ml of 0.5N solution
Answers
Answered by
1
Answer:
Explanation: molarity = normality *n-factor and n-factor is 2 so
Molarity will be 2*0.5=1
Molarity*molar mass* volume= weight
1*105*100/1000=10.5gm
Answered by
0
Answer:
Explanation: molarity = normality *n-factor and n-factor is 2 so
Molarity will be 2*0.5=1
Molarity*molar mass* volume= weight
1*105*100/1000=10.5gm
Explanation:
MARK ME BRAINLIEST PLS
Similar questions