Question

calculate the weight of na2co3 present in 500ml of 0.5 Normality solution ​

Answer 1

Answer:

125 g

Explanation:

1000mL of solution contains 0.5 equivalence Na2CO3

then,

500mL of solution contains (0.5/2)= 0.25 equivalence of Na2CO3

(unitary method)

now , we know the molecular weight of Na2CO3 is = 106

hence, 500mL of solution contains:

0.25*500 g =125 g of Na2CO3