calculate the weight of NaCl present in 250 g of 0.01 m solution
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Given: 0.01 molal Sloution
Molality = No. of moles/mass of solvent in kg
⇒0.01 = n/0.25
⇒n=0.0025
Molecular Weight of NaCl=23+35.5 = 58.5 a.m.u
⇒ Weight = No. of moles * Molecular Weight
⇒Weight = 0.0025*58.5=0.14625g
The Weight of NaCl = 0.14625 grams
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