Question

calculate the weight of nitrogen present in 0.5 moles of ammonia

Answer 1

Nitrogen present in 1 mole ammonia =1 mole
=14g
So nitrogen present in 0.5 mole ammonia =14g×0.5=7g

Answer 2

Answer:

Explanation:

1 mole of NH3 Has 1 mole of N atom.

Molar mass of nitrogen =14 g

1 mole NH3 =14 g

0.5 mole NH3 =14×0.5= 7g

And that's the answer...