Question

calculate the weight of oxalic acid for preparing 0.1(N) solution in a 500ml volumetric flask​

Answer 1

Given:

Calculate the weight of oxalic acid for preparing 0.1(N) solution in a 500ml volumetric flask​?

To find:

The weight of oxalic acid

Solution:

Finding the equivalent weight of oxalic acid:

We know,

$\boxed{\bold{Equivalent \:weight = \frac{Molecular \:weight\:(M.W.)}{Valency(n)} }}$

The molecular weight of oxalic acid = 126 g/mol

n-factor = 2

∴ Equivalent weight = $\frac{126}{2} = 63$

Finding the weight of oxalic acid:

We know,

$\boxed{\bold{Normality = \frac{Weight \times 1000}{Eq. weight \times Volume (in\: ml)} }}$

Now, on substituting the values of Normality = 0.1(N), Volume = 500 ml and Eq. weight = 63, in the formula above, we get

$0.1 = \frac{Weight\: \times\: 1000}{63\: \times\: 500} }}$

$\implies 0.1 = \frac{Weight\: \times\: 2}{63} }}$

$\implies 0.1 \times 63 = Weight\: \times\: 2$

$\implies Weight = \frac{0.1 \times 63}{2}$

$\implies \bold{Weight = 3.15\:g}$

Thus, the weight of oxalic acid required for preparing 0.1(N) solution in a 500ml volumetric flask​ is → 3.15 g.

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