Question

Calculate the weight of oxygen gas envoloved when 5.0 g of KCIO3 are completely decomposed thermally ​

Answer 1

Answer:

weight of O2 formed = 1.95grams

Explanation:

2KClO3 -----> 2KCl + 3O2

2mole KClO3 gives 3mole O2

1mole KClO3 gives (3/2) moles O2

mole of KClO3 present= 5/122.5

therefore

(5/122.5) moles of KClO3 gives => (3/2)×(5/122.5) moles of O2

weight of O2 formed = (3/2)(5/122.5)×(32)

weight of O2 formed = 1.95grams