calculate the weight of oxygen required to produce 54gms of water from following reaction h2 + 1/2o2= h2o
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u need 48 gm oxygen. clear...
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Given : Weight of water : 54 grams
Reaction of production of water : H2 + 1/2O2 --> H2O
Find : Weight of oxygen required to produce 54 gram of water.
Solution : Number of moles of water required : 54/18
Number of moles of water : 3
As per given reaction, 1 mole of water will be formed by 0.5 moles of oxygen.
Hence 3 moles of water will form by : 0.5*3 = 1.5 moles of oxygen.
Weight of oxygen : 1.5*32
Weight of oxygen : 48 gram.
Thus, the amount of oxygen required for production of 54 grams of water is 48 gram.
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