Question

calculate the weight of quicklime formed when 500 grams of limestone is heated(atomic mass of CA is 40 and C is 12 and O is 16). find the answer

Answer 1

atomic mass of limestone (CaCO3) = 40 + 12 + 3×16 = 100 amu
therefore in 1 mole of CaCO3 present in 100 g
therefore 5 moles in 500 g
reaction:
CaCO3 (∆)→ CaO + CO2
atomic mass of CaO = 40 + 16 = 56 amu therefore 5 moles will weigh 280 g
atomic mass of CO2 = 12 + 2×16 = 44 amu
therefore 5 moles will weigh 220 g

therefore mass of CaO formed will be 280 g

Answer 2

Answer:

Explanation:

atomic mass of limestone (CaCO3) = 40 + 12 + 3×16 = 100 amu

therefore in 1 mole of CaCO3 present in 100 g

therefore 5 moles in 500 g

reaction:

CaCO3 (∆)→ CaO + CO2

atomic mass of CaO = 40 + 16 = 56 amu therefore 5 moles will weigh 280 g

atomic mass of CO2 = 12 + 2×16 = 44 amu

therefore 5 moles will weigh 220 g

therefore mass of CaO formed will be 280 g