Question

Calculate the weight of single atom of silver?

Answer 1

1 mole of Ag ====> 6.023* 10^23 atoms

108 g ===> 6.023*10^23

xg =====> 1

108 * 1 = 6.023 * 10^23 * x

108 / 6.023 * 10^ -23 = x.

x = 18* 10^ -23 g

weight of single atom of silver is 18* 10^ -23 g


hope helped!