calculate the weight of sodium hydroxide required to prepare 0.5 m and its solution in two liter volumetric flask
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2 L volumetric flask means a 2L solution of NaOH.
Total moles of NaOH formula units in this solution is 2 litres×0.5 moles per litre=1 mole of NaOH.
So 1 mole of solid NaOH is required to prepare the solution.
Which equals to 1mole× 40 gram / mole NaOH=40 gram NaOH.
Molar mass of NaOH is 40 gram/mole.
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