Question

Calculate the weight of sodium hydroxide tequired to exactly nuetralise 50 ml of a solution of sulphuric acid containing 9.0 gram per litre ( Ans . 0.3673 gram )​

Answer 1

Answer:

The balanced chemical equation is as follows:

H

3

PO

4

+3NaOH→Na

3

PO

4

+3H

2

O.

Here, 1 mole H

3

PO

4

is required to neutralize 3 moles of NaOH.

One mole (98 g) of phosphoric acid will neutralize 3 moles (3×40=120 g) of sodium hydroxide.

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