Calculate the weight of sodium hydroxide tequired to exactly nuetralise 50 ml of a solution of sulphuric acid containing 9.0 gram per litre ( Ans . 0.3673 gram )
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Answer:
The balanced chemical equation is as follows:
H
3
PO
4
+3NaOH→Na
3
PO
4
+3H
2
O.
Here, 1 mole H
3
PO
4
is required to neutralize 3 moles of NaOH.
One mole (98 g) of phosphoric acid will neutralize 3 moles (3×40=120 g) of sodium hydroxide.
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