Question

calculate the weight of substance deposited in current of 2.5 ampere is passed through and electrolyte solution for 20 minutes given E.C.E.=0.000304

Answer 1

W=Zit= 0.000304×2.5×20×60=0.000304×300
= 0.0912g

Answer 2

The weight of the substance deposited is $= 0.0912g$

Explanation:

• The amount of mass of an element liberated during the electrolysis is directly proportional to the amount of electricity that passes through the electrolyte.

• Given  current of $2.5 ampere$

• Time=$20 minutes$ to be converted to seconds which will be equal to $1200 sec$

• The formula for finding the weight of the substance is as follows $w=ZIt$

• substituting the value in the formula and the value is  $E.C.E.=0.000304$

            $w=Zit$

            $w= 0.000304$ ×$2.5$ ×$1200$

             $w=0.0912g$

• Weight of substance deposited in current of$2.5 ampere$is passed through and electrolyte solution for$20 minutes$ is equal to $0.0912g$.