Question

calculate the weight of the structure given below assume the suitable dimensions is required length is equal to 8 metre R=50cm r=25cm​

Answer 1

Step-by-step explanation:

Length of the room = 8m 25cm = 825 cm

Breadth of the room = 6m 75cm = 675 cm

Height of the room = 4m 50cm = 450 cm

Prime factorization of 825, 675 and 450 are as follows:

825 = 3×5×5×11

675 = 3×3×3×5×5

450 = 2×3×3×5×5

Common factors = 3×5×5

H.C.F. = 75

Hence, H.C.F. of 825, 675 and 450 is 75.

Therefore the length of the longest tap is 75 cm which can measure the three dimensions of the room exactly.

Answer 2

Step-by-step explanation:

Length of the room = 8m 25cm = 825 cm

Breadth of the room = 6m 75cm = 675 cm

Height of the room = 4m 50cm = 450 cm

Prime factorization of 825, 675 and 450 are as follows:

825 = 3×5×5×11

675 = 3×3×3×5×5

450 = 2×3×3×5×5

Common factors = 3×5×5

H.C.F. = 75

Hence, H.C.F. of 825, 675 and 450 is 75.

Therefore the length of the longest tap is 75 cm which can measure the three dimensions of the room exactly.

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