Question

Calculate the weight of zinc required to produce 2.24 litres of hydrogen . When it reacts with excess of Hcl​

Answer 1

Answer:

0.65g Zn+H

2

SO

4

→ZnSO

4

+H

2

At STP 224 mL of hydrogen corresponds to

1000×22.4

224

=0.01 moles of hydrogen. They will be produced from the reaction of 0.01 mole of Zn with 0.01 mole of sulphuric acid. Hence, the mass of zinc required is 65.38×0.01=0.65 g.

Explanation:

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