Question

Calculate the work done by a 2N force (directed at a 30 o angle to the vertical) to move a 500g box
through a horizontal distance of 400cm across a rough floor at a constant speed of 0.5m/s.

Answer 1

The force that is responsible for doing the work here is the horizontal force

Horizontal force = Fsin30 = 2*1/2 = 1N

Mass = 500g = 0.5kg

Distance moved = 400cm = 4m

Work done = Force*Displacement

                   = 1*4 = 4J

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Answer 2

Answer:

w=work done

w=4J

Explanation:

Note:

-that the 30 degrees are vertical to the box thus we would do 90-30=60

as we have to calculate the horizontal work not the vertical

-Mass and speed are not required but are given to either confuse the student or complete the question

-The displacement is in centimeters but the equation works for only the meters unit thus 400cm is equal to 4m

-Force applied is 2N

- * stands for multiplication when I am solving it

Hence,

W=2*cos60*4

w=cos60*8

w=0.5*8

w=4J

Remember to keep the units as their SI Unit