Question

Calculate the work done by a 47 n force pushing a pencil 0.26 m

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Work\:Done(W)=12.22J}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Force (F) = 47N

• Distance (s) = 0.26m

$\large\underline\pink{\sf To\:Find: }$

• Work done (W) = ?

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$\large{♡}$${\boxed{\sf Work\:Done(W)=Force(F). Distance}}$

$\large\implies{\sf 47×0.26}$

$\large\implies{\sf 12.22J }$

$\huge\red{♡}$$\large\red{\boxed{\sf Work\:Done(W)=12.22J}}$

Answer 2

Answer:

The work done by a force of $49N$ pushing a pencil $0.26m$ is equal to $12.22$ Joules.

Explanation:

Work done:

• Work is defined as the product of the component of force in the direction of displacement and the magnitude of the displacement.
• Joule is the S.I unit of work.
• To calculate the work done, mathematical formula is:

                                 $w=F.d$    where

'$w$' is work done

'$F$' is force

'$d$' is displacement

Step 1:

Given, force $F=47N$

            $d=0.26m$

Work done is equal to:

$w=F.d\\w=(47).(0.26)\\w=12.22J$

Work done by a $47N$ force in pushing a pencil $0.26m$ is equal to$12.22$ Joules.