Calculate the work done by a force of 15N Acting along a direction 60 to the horizontal for displacing a block through a distance of 6 meters along the horizontal surface.
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Explanation:
here is the answer
that is 60Nm
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Answer:
45J
Explanation:
work=F s (cos theta)
force=15N
displacement=6m
cos theta= 60°
work= 15×6×1/2
=45J
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