Science, asked by karthik1024W, 5 months ago

Calculate the work done by a force of 30N in lifting a load of 2kg to a height of 10m (g = 10 ms-2)

Answers

Answered by shweta7289
0

Explanation:

work done = m g h

= 2× 10×10

=200 joule

Answered by Anonymous
6

Answer:

\huge\mathfrak\red{answer :- }

Given :

F = 30 N,m = 2 kg,h = 10 m,g=10m/s.

gravitational force F = mg

the distance covered h = 10 m

W = Fh

= 30×10

{\large{\boxed{\mathcal{{W =300joule}}}}}

Explanation:

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