Question

Calculate the work done by a force of 30N in lifting a load of 2kg to a height of 10m g=10m/s

Answer 1

work done=mgh
2×10×0.1= 2Joule


I hope it will help u

Answer 2

$\huge \fbox{Answer}$

$\large { \underline {\underline {\red{\frak{Given}}}}}$

$\mapsto \sf{Force\:applied\:on\: object=30N}$

$\mapsto \sf{Height \: of \: body(h)=10m}$

$\mapsto \sf{Gravity \: of \: body(g)=10m {s}^{ - 1} }$

$\large { \underline {\underline {\red{\frak{To \: find}}}}}$

$\leadsto \sf{Work \: done(W) \: by \: object. }$

$\large { \underline {\underline {\red{\frak{Formula \: required}}}}}$

$\pink \star {\boxed {\sf{Work \: done (W)=Force(f)×Displacement(s)}}} \pink \star$

$\large { \underline {\underline {\red{\frak{According \: to \: Question}}}}}$

${{ :\implies {\sf{Work \: done (W)=Force(f)×Displcement(s)}}} }$

${{ :\implies {\sf{Work \: done (W) = 10×30}}} }$

${{ :\implies {\sf{Work \: done (W) = 300N}}} }$