Calculate the work done by a man weighing 70kg in climbing up a ladder 20m high. (g=9.8m/s2)
Answers
Answered by
3
Answer:
13720J
Explanation:
here
mass(m)=70kg
height(h)=20m
acceleration due to gravity(g)=9.8m/s²
we have
workdone =mgh
=70*9.8*20
=13720J
Answered by
12
ⓢⓞⓛⓤⓣⓘⓞⓝ ⤵️
Given:-
1)mass of the body =70kg
therefore force applied on him =m×g=70×9.8=686 N
N=Newton
i.e this are in S.I unit
displacement of the body=20m
Formula of work =Force ×displacement
i.e W=FD
calculate the work:-
information about work:-
W = F * d: ... We know that work done is defined as the multiplication of magnitude of displacement d and the component of the force that is in the direction of displacement. Work Done Formula. Work done via force (F) is equal to the change in kinetic energy.
work =Force ×displacement
=686×20=13720 joule
Final answer:-13720 joule
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