Physics, asked by nishantkumar162615, 4 months ago

Calculate the work done by a man weighing 70kg in climbing up a ladder 20m high. (g=9.8m/s2)

Answers

Answered by john332
3

Answer:

13720J

Explanation:

here

mass(m)=70kg

height(h)=20m

acceleration due to gravity(g)=9.8m/s²

we have

workdone =mgh

                =70*9.8*20

                =13720J

Answered by MISSTHUNDER
12

ⓢⓞⓛⓤⓣⓘⓞⓝ ⤵️

Given:-

1)mass of the body =70kg

therefore force applied on him =g=70×9.8=686 N

N=Newton

i.e this are in S.I unit

displacement of the body=20m

Formula of work =Force ×displacement

i.e W=FD

calculate the work:-

information about work:-

W = F * d: ... We know that work done is defined as the multiplication of magnitude of displacement d and the component of the force that is in the direction of displacement. Work Done Formula. Work done via force (F) is equal to the change in kinetic energy.

work =Force ×displacement

=686×20=13720 joule

Final answer:-13720 joule

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