Calculate the work done by a man who lifts 6 bricks, each weighing 3N and puts them at a height of 2.3m above the ground.
Answers
Answered by
11
Answer:
work done = displacement × force
here , the man has not displaced at all.
therefore ,
W = 0 × F
W = 0
hence , work done = 0
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Answered by
61
Answer:
41.4 joule
Step-by-step explanation:
total force acts on 6 bricks
= 6 × 3N = 18N (Force)
height/length above the ground = 2.3m
work = Force × length
Work =18 × 2.3 = 41.4 Joule
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