Question

calculate the work done by a motor lifting a 20kg mass through a vertical distance of 6m

Answer 1

Answer:

w = 1176 J  or 1.176KJ

Explanation:

we know that,

work = m × g × h

where as,

given that,

mass = 20kg

g = 9.8m/$s^2$

height = 6m

now ,

put the value

w =  m × g × h

w = 20 × 9.8 × 6 J

w = 1176 J  or 1.176KJ