calculate the work done by a person in lifting a load of 20 kg from the ground and placing it on a 1 metre high table
Answers
Answered by
7
F=mg
=20×9.8
= 196kg.m/s^2
then
work done=F×s
= 196×1
=196 joule
=20×9.8
= 196kg.m/s^2
then
work done=F×s
= 196×1
=196 joule
Answered by
4
Work done = Change in potential energy
= mg (h₂ - h₁)
= 20 kg × 9.8 m/s² × (1 m - 0 m)
= 196 Joule
Work done to lift the load is 196 Joule
Similar questions