calculate the work done by a person in lifting a load of 20kg from the ground and placing it on a 1 m high table.
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Answered by
1
The work done by MAN will be positive because direction of Force applied and Displacement is same.
So, Work Done = (20)(9.8)(1) = 196 J
* Note-
Work Done by GRAVITY will be (-ve).
So, Work Done = (20)(9.8)(1) = 196 J
* Note-
Work Done by GRAVITY will be (-ve).
Answered by
5
Work done = Change in potential energy
= mg (h₂ - h₁)
= 20 kg × 9.8 m/s² × (1 m - 0 m)
= 196 Joule
Work done to lift the load is 196 Joule
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