Calculate the work done by a47 N force pushing a pencil 0.26 m
Answers
⠀⠀⠀
⠀⠀⠀ Given :-
✰ Force = 47 n
✰ Distance = 0.26
We know that,
⠀ ⠀⠀⠀⠀⠀ ⠀⠀⠀⠀✰ Work = Force × Distance
⠀ ⠀⠀⠀⠀✰ Work = 47 × 0.26
⠀ ⠀⠀⠀⠀✰ Work = 12.22 joule..
Hence,
- ⠀ ⠀⠀⠀⠀⠀ ⠀⠀⠀⠀✰ 12.22 joule is required value...
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Answer:
It depends, between 0.06−0.12 J .
Explanation:Work = Fdcosθ
Meaning the work is done effectively only by the component of the force that is in (or opposite to) the direction traveled by the object when it is being pushed or pulled.
Hence, it depends on the direction, which is not specified, of the force being applied.
If the force is applied directly opposite to the friction, then work done by the force is
(a) W = Fd =0.47 N⋅ .26 m= 0.12 Nm =0.12 J
(Note: keep the answer in 2 significant digits only because that is how the force and distance are given, in 2 significant digits.)
However, if the force is directed at an angle, then its component Fcosθ
must be at least as much as the friction, otherwise, the pencil won't move. In this case, the force is effectively exerting only Fcosθ=0.23 N
on the pencil. Thus,
(b) W = (Fcosθ)d = 0.23 N⋅ .26 m = 0.060 J
Note that in Case (a), the force is bigger than the friction, hence the pencil actually accelerates, meaning part of the work done is converted into kinetic energy of the pencil. In Case (b), there is no acceleration, i.e., constant speed, the pencil's kinetic energy does not change.
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