Physics, asked by Rajarao661, 1 year ago

Calculate the work done by the brakes of a car of mass 1000kg when its speed is reduces from 20m/s to 10m/s ?

Answers

Answered by Shubhendu8898
13

Answer:- = 150 kJ

Step by Step Solution:-

We have  given  that the  car  is  moving  with  a particular speed of  20m/s and later with 10m/s

So car  have a Kinetic  energy due to its speed. We have  to work against this Kinetic Energy.

We have,

m = 1000 kg

Initial speed(u) =  20 m/s

Final Speed (v) = 10

Using Work - Energy Theorem,

Work done = m/2(u² - v²)

= 1000/2(20² - 10²)

= 500(20 + 10)(20 - 10)

= 500 × 30 × 10

= 150000 J

= 150 kJ

Answered by Anonymous
8

We are given with :

Initial Velocity = u of the body = 20 m/S

Final Velocity= v of the body = 10 m/S

Mass of the body = m = 1000 kg

We know that the work done =

 \frac{m(  {u}^{2} -  {v}^{2} ) }{2}  \\  \\  \frac{1000(400 - 100)}{2}  \\  \\  \frac{300000}{2}  = 1500000

= 1500000 J = 150 KJ

The required work done is 150 KJ.


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