Question

calculate the work done during isothermal expansion of 1 mol of an ideal gas from a volume of 1dm¹ to 1m³ against a constant pressure of 100 kpa​

Answer 1

Explanation:

Work done during isothermal expansion-

Given,

n=1

T=300k

p

1

=10 atm

p

2

=1 atm

W=2.303nRTlog

p

2

p

1

⇒2.303×1×8.314×300×log10=5744.1 J

Answer 2

Answer:

5744.1 J

Explanation:

worrk done during isothermal expansion-

given,

n=1

T=300k