calculate the work done during the expansion of an ideal gas
Answers
Answered by
0
Answer:
I don't know broo I am sorry
Answered by
0
Answer:
When an ideal gas is subjected to isothermal expansion (∆T = 0) in vacuum the work done w = 0 as pex=0. As determined by Joule experimentally q =0, thus ∆U = 0. For isothermal reversible and irreversible changes; equation 1 can be expressed as: Isothermal reversible change: q = -w = pex(Vf-Vi)
Similar questions