Question

calculate the work done during the reaction represented by the following thermochemical equation as 300k.
CH4 + 2O2 -------> CO2 +2H2O

1. +4.988 kg.
2.-4.988 kg.
3.-49.88 kg.
4.+49.88 kg. ​

Answer 1

Answer:

Explanation:

+4.988kJ

Explanation:

Ch4+2o2=co2+h2o

Ch4 co2 and o2 are in gaseous state so

Delta ng ie no of moles of gaseous product-no of moles of gaseous reactant

=1-3=-2

W=delta ng RT

W=-2×8.314.300

W=4988 J

W=+4.988kJ

Answer 2

Answer:

answer:

option 2nd +4.988 is ur answer

hope it helps...

thanku☺

#divu.