Calculate the work done if a wire is loaded by mg weight and increase in length is l
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The stress will be required for a length to a wire will be equal to the load being' produced elongation e in a wire,the rise in temperature required
The Work was done on the wire during stretching = average force x extension = ½ Fe
Work was done if a wire is loaded by = 1/2Fl
So the mg weight and increase in length is l
=Mgl/2
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Answer:
Mgl/2
Explanation:
Work done=1/2YA/l(L)^2
1/2FL
1/2Mgl
Mgl/2
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