calculate the work done if Temperature is change from 0°to 200° at 1 atm is
100cal
200cal
400cal
800cal
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3
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0
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Solution:- (D) 120J
As the work is done by the system and heat is supplied to the system.
Therefore,
q=100 cal=420J
w=−300J
Now from first law of thermodynamics,
ΔU=q+W
∴ΔU=420+(−300)
⇒ΔU=120J
Hence the change in internal energy during the process is 120
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