Calculate the work done in blowing a soap bubble of radius 5 cm
cm if the surface tension of soap solution is 30 dyne/cm
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Answer:
Work done in blowing a soap bubble W=2T(A 2 −A 1 )
now r 1 =0.05m ,r 2 =0.1m
So W=2T(4πr^2/2−4πr ^1/2 )=8πT(0.1 ²
−0.05 ² )=6.6×10^ −3 J
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