Calculate the work done in blowing a soap bubble to a radius 1 cm the surface tension of a soap solution is 2.5×10 raised-2N/m
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Explanation:
T=25×10
−3
N/m
Initial radius=10㎝
Final radius=20㎝
Final surface area =△A=2×(4πr
f
2
−4πr
i
2
)
Work done=T×△A
△A=2×
⎣
⎢
⎡
4π(
100
20
)
2
−4π(
100
10
)
2
⎦
⎥
⎤
=
(10)
2
2×4π
[4−1]=
(10)
2
24π
W=T×△A
W=
(10)
2
25×10
−3
×24π
W=1885.71×10
−5
W=0.018857J
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