Question

calculate the work done in bringing a body of mass 10 kg moving with a velocity of 20 m/s to rest​

Answer 1

Answer:

1000J

Explanation:

kinetic energy of the body = 1/2mv^2

KE = 1/2×10×20×20=1000J

therefore to stop the body we should apply an equal amount of energy (workdone) to stop the body