Question

Calculate the work done in expanding isothermally 5 mol of an ideal gas from 1-20 L at zero degree Celsius.

Answer 1

Answer:

The work done for an isothermal process is given by:

Work done (W)=−nRTln(

V

1

V

2

)=−1×8.314×300×ln(

25

250

)

∴ Work done(W)=−5744J