Question

Calculate the work done in increasing the radius of a spherical soap bubble slowly from 1cm to 5cm. (Surface tension of soap solution = 2×10^-3N/m)​

Answer 1

Answer:

Work done in blowing a soap bubble W=2T(A2 − A1 )

now r 1 =0.05m ,r 2 =0.1m

So W=2T(4πr 2/2 −4πr 2/1 )=8πT(0.12 −0.052 )=6.6×10 −3 J

Explanation:

Understand the answer properly pls