Calculate the work done in lifting 200 kg of water through a height of 6m/s given g=10m/s
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Answered by
3
We know that work done is given by F.ds
Here F = ma => 200×10 => 2000N
and ds = 6m
As the Man is waling in particular direction Therefore ∅ = 90°
Hence work done will be zero .
Because W = FsCos∅
and cos90° = 0
Here F = ma => 200×10 => 2000N
and ds = 6m
As the Man is waling in particular direction Therefore ∅ = 90°
Hence work done will be zero .
Because W = FsCos∅
and cos90° = 0
Answered by
3
work=force *displacement
since force =mass *acceleration
work=200kg*10*6m
w=2000N*6m
w=12000joules
plzzzzzzzzzzz like it
since force =mass *acceleration
work=200kg*10*6m
w=2000N*6m
w=12000joules
plzzzzzzzzzzz like it
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