Question

calculate the work done in lifting 200kg of a mas through a vertical distance of 6m. Assume g = 10 m/s^2

Answer 1

Hi friend,

Work done= potential energy

Work done = mgh

Work done= 200×6×10

Work done= 1200J (or) 12kj.

Hope this helped you a little!!!!

Answer 2

Given:

The mass of the object = 200kg

The distance through which the object is lifted = 6m

To Find:

The work done in lifting the object

Solution:

Work done = Force X Distance X cos ∅

where ∅ is the angle between the force and the distance

∴ WD = F s cos ∅

Force applied by gravity during the process is in the downward direction while the displacement of the box is upwards.

⇒ ∅ = 180

Hence, WD by gravity = (mg) . s . cos 180°

= - 2000J

The work done by the person is equal in magnitude but opposite in direction to the work done by gravity.

Hence, the work done by a person in lifting 200kg of a mass through a vertical distance of 6m is 2000J.