Question

Calculate the work done in lifting 200kg of a mas through a vertical height of 6m. Assume g = 10 m/s^2

Answer 1

mass = 200 kg
height = 6 m
g       = 10 m/s^2
workdone = potential energy 
                = mgh
                 = 200 x 6 x 10
                 = 12000 J

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Answer 2

Work done  

W = mgh

m = 200 kg

g = 10m/s^2

h = 6m

W = mgh

Substitute the values

W = 200 × 10 × 6

W = 12000 Joule