Math, asked by prinncebharti55117, 11 months ago

calculate the work done in lifting 200kg of water through a vertical distance of 6 metre.assume G=9.8 m/s2.​

Answers

Answered by sagwalsatyam13
1

Answer:

Step-by-step explanation

Mass=200kg

Height=6m

g=9.8

Work done against gravity=mgh=200*6*9.8=11,760joules=11.760 kilojoules

Answered by Anonymous
2

__________________________________________

 \mathbf \red{given}

M=200 Kg

G=9.8m/s²

H=6m

 \mathbf \red{to \: find \: out}

Work done =?

 \mathbf \red{formula \: used}

We know that

work done =mgh

 \mathbf \red{solution}

Work done =mgh

=>putting the value

Now,

work done =200×9.8×6

=120×98

=11760j

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