Question

calculate the work done in lifting 200kg of water through a vertical height of meters assume g equal to 10 m/s^2

Answer 1

mass 200 kg
g 10 m/s^2
h 6m
W=m×g×h
= 200×10×6
=12000joule...

Answer 2

Answer:

The correct answer is  $12KJ$  . The height is missing in the question, but correct question has height given= 6m

Explanation:

• Work done is defined as the product of the force applied to the object and displacement of the object.

$work done = force * displacement$

• Force is the product of mass and acceleration.  

$Force = mass * acceleration$

• Thus work done =

$mass * acceleration * displacement$

Mass, = $200Kg$

Vertical distance= displacement, = $h = 6m$

acceleration $= g= 10ms^{2}$

Now we have to find the work done,

Therefore, Work done is given by the formula,

$work done = mgh$

$200 *6 * 10\\12000J\\12 KJ$

Amount of work done is 12KJ.

• In physics, mass is a quantitative measure of inertia, which is a fundamental feature of all matter. It is, in effect, the resistance that a body of matter provides to a change in its speed or position when a force is applied to it. The smaller the change caused by an applied force, the higher the mass of the body.
• The rate of change of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, however this is not always the case. When an object goes on a circular course with a constant speed, it is still accelerating since its velocity direction changes.

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