Math, asked by athiranil15, 11 months ago

calculate the work done in lifting 300kg of water by 4m suppose g= 10m/sec²​

Answers

Answered by Anonymous
3

Work done = potential energy gained by the water

=mass * g *height

=300×10 ×4=12000 joules

Thanks for asking

Answered by IsitaJ07
16

Answer :

 \huge{ \huge{ \red{ \boxed{ \green{ \: 12000 \:  \: }}}}}

Given :

Mass = 300

Height = 10

g = 40

Step-by-step explanation:

Work Done = Potential Energy (gained by water)

= Mass × g × height

= 300 × 10 × 4

= 12000 joules

Hence,

the work done in lifting 300kg of water by 4m suppose g= 10m/sec² will be 12000 joules

#BAL #AnswerWithQuality

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