Question

calculate the work done in lifting a 200kg of water through a vertical distance of 6m. Assume g=10m/s2​

Answer 1

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$\huge{\underline{\underline{\sf{\green{SOLUTION:-}}}}}$

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$\sf{\underline{\red{Answer-}}}$

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• The work done is 12000 Joules.

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$\sf{\underline{\red{Given-}}}$

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• The work done in lifting a 200kg of water through a vertical distance of 6m. (Assume g = 10m/s²).

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$\sf{\underline{\red{Calculate-}}}$

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• We have to calculate the work done.

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$\sf{\underline{\red{Explanation-}}}$

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$\sf{\underline\blue{Formula\:Used\:Here-}}$

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$\bigstar\boxed{\sf{\pink{W=m \times g \times h}}}$

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$\sf \: Here:-$

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$\longrightarrow\sf \: Mass \: of \: water, \: m=200kg$

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$\longrightarrow\sf \: Acceleration \: due \: to \: gravity, \: g=10 \: m/ {s}^{2}$

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$\longrightarrow\sf \: Height, \: h=6m$

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$\sf{\underline{\red{Now\:Putting\:the\:values:-}}}$

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$\longrightarrow\sf \: W=200 \times 10 \times 6$

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$\longrightarrow\sf \: W=12000 \: Joules$

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• Thus, the work done is 12000 Joules.

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${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{</p><p>~cαndчflσѕѕ♡ :)}}}}}}$

Answer 2

Answer:

sorry babes I didn't know..................