Question

calculate the work done in moving a charge of 2 coulomb from a point at 220 volts to another points at 230 volts​

Answer 1

Answer:

We know that potential difference = Work done/Charge moved.

In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.

Thus, the potential difference = v2-V1 = 230-240 = 10 V

Therefore, Work done = Potential difference * Charge moved.

That is, 10 * 5 = 50 Joules.

Explanation:

Answer 2

Answer:

Q = 2C

V1 = 220V

V2 = 230V

Net V = V2 - V1

Net V = (230 - 220)V

Net V = 10V

Therefore, V = 10V

V = W/Q

W = V X Q

W = 10 X 2

W = 20J

HOPE IT HELPS YOU DEAR.

THANKS