Calculate the work done in moving a charge of 4 columcolumb from a point at 220 volts to another point at 230 volts
Answers
Answered by
18
Here,
We have Q(charge) = 4 coulomb
V (potential difference)= 230V - 220V = 10V
Work done,
W = VQ
W= 4 × 10
W = 40 J
We have Q(charge) = 4 coulomb
V (potential difference)= 230V - 220V = 10V
Work done,
W = VQ
W= 4 × 10
W = 40 J
Answered by
7
here is your answer OK
V1=220
V2=230
POTENTIAL DIFFERENCE = V2 - V1 =
230V-220V=10V
CHARGE= 4C
Formula....
POTENTIAL DIFFERENCE = WORK DONE / CHARGE
10V=W/4C
W=10*4 J
W=40j
V1=220
V2=230
POTENTIAL DIFFERENCE = V2 - V1 =
230V-220V=10V
CHARGE= 4C
Formula....
POTENTIAL DIFFERENCE = WORK DONE / CHARGE
10V=W/4C
W=10*4 J
W=40j
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