Physics, asked by ss1682762, 1 year ago

Calculate the work done in moving a charge of 4 columcolumb from a point at 220 volts to another point at 230 volts

Answers

Answered by Anonymous
18
Here,

We have Q(charge) = 4 coulomb

                       
V (potential difference)= 230V - 220V = 10V


Work done,

W = VQ

W= 4 × 10

W = 40 J

Answered by vikram991
7
here is your answer OK

V1=220
V2=230
POTENTIAL DIFFERENCE = V2 - V1 =
230V-220V=10V

CHARGE= 4C

Formula....

POTENTIAL DIFFERENCE = WORK DONE / CHARGE

10V=W/4C
W=10*4 J
W=40j

Similar questions