Question

Calculate the work done in moving a charge of 4 coulombs from a point at 220 volts to another point at 230 volts....​

Answer 1

Given:

A charge of 4 C is moved from a point at 220 V to another point at 230 V

To Find:

Work done in moving charge

Solution:

We know that,

• When a charge is moved from one point to other , the potential difference V is given by

$\pink{\boxed{\bf{V=V_{2}-V_{1}}}}$

where,

V₂ is the potential of final point

V₁ is the potential of initial point

• Work done W in moving a charge from one point to other is given by

$\pink{\boxed{\bf{W=V\times q}}}$

where,

V is the potential difference of initial and final point

q is the magnitude of the charge of charged particle

$\rule{190}{1}$

Let the potential difference of charge be V

So, according to question

⇒ V= 230-220= 10 V

$\rule{190}{1}$

Now, let the work done in moving the given charge be W

So,

$\longrightarrow\rm{W=V\times q}$

$\longrightarrow\rm{W=10\times4}$

$\longrightarrow\rm\green{W=40\:J}$

Hence, the work done in moving a charge of 4 C from a point at 220 volts to another point at 230 volts is 40 J.

Answer 2

Given ,

A charge of 4 coulombs is moved from a point at 220 volt to another point at 230 volt

As we know that ,

The work done to move a unit charge from one point to another point is called potential difference

$\star \: \: \bold{V_{b} - V_{a} = \frac{ W_{ab} }{q}}$

Thus ,

$\sf \Rightarrow 230 - 220 = \frac{W}{4} \\ \\\sf \Rightarrow 10 = \frac{W}{4} \\ \\ \sf \Rightarrow W = 40 \: \: joule$

$\therefore \sf \bold{ \underline{The \: work \: done \: is \: 40 \: joule}}$