Question

Calculate the work done in moving a charge of 5 coulombs from a point at a potential of 210 volts to another point at 240 volts

Answer 1

Answer:

150 Joules

Explanation:

q = 5C

$V_{B}$ = 210 V

$V_{A}$ = 240 V

W = $q (V_{B} - V_{A})$

W = 5(240-210)

W = 5(30)

W = 150 Joules

Answer 2

Answer:

Given :-

• A change of 5 coulombs from a point at a potential of 210 volts to another point at 240 volts.

To Find :-

• What is the work done.

Formula Used :-

♣ Work Done Formula :

$\longrightarrow \sf\boxed{\bold{\pink{W =\: QV}}}$

where,

• W = Work Done
• Q = Charge
• V = Potential Difference

Solution :-

First, we have to find the potential difference :

Given :

★ Potential Difference at first point = 210 V

★ Potential Difference at second point = 240 V

Then,

$\implies \sf Potential\: Difference =\: 240\: V - 210\: V$

$\implies \sf\bold{\green{Potential\: Difference =\: 30\: V}}$

Now, we have to find the work done :

Given :

★ Charge = 5 Coulombs

★ Potential Difference = 30 V

According to the question by using the formula we get,

$\longrightarrow \sf W =\: 5 \times 30$

$\longrightarrow \sf\bold{\red{W =\: 150\: J}}$

∴ The work done is 150 J .