Question

Calculate the work done in moving a charge of 5C from a point at 20mV to a point at 40mV.​

Answer 1

Answer:

Explanation:

We know that potential difference = Work done/Charge moved.

In this case, V =20 mV and V2 = 40 mV. The mount off charge moved  = 5 C.

Thus, the potential difference = v2-V1 = 40-20 = 20 V

Therefore, Work done = Potential difference * Charge moved.

That is, 20 * 5 = 100 Joules.

Hence, the  work done in moving a charge of 5 coulombs from a point at 20 volts to another point at 40  volts is 100 J.

Answer 2

Given the charge, q = 5 C

The initial potential at a point, V = 20 V.

The final potential at another point, v = 40 V

The relationship between work done, charge and change in potential difference is given as :-

$\bold{\sf{W=q\Delta V}}$

On substituting the given values, we get :-

$\sf{W=5C\times (40V-20V)}$

$\sf{W = 5 \times 20}\\\\\boxed{\sf{W = 100\ J}}$