Question

calculate the work done in open vessel at 27 degree Celsius when 28g Fe reacts with h2SO4<br /><br />Please say correct answer and I will mark you as branliest ​

Can anyone help

Answer 1

Answer:

reaction involved is :

Fe(s) + 2 HCl(aq) →→ FeCl2 + H2

Work done (W) = - P (V2 - V1)

Mass of Fe used for reaction = 113 g

Molar mass of Fe = 56 g/mol

Moles of Fe used =1135611356 moles = 2.018 moles

Thus moles of H2 produced in the reaction are = 2.018 moles

For the reaction V1 = 0 ( Initially no H2 is produced)

and V2 = nRT/P

Thus W = - P (V2 - 0) = - PV2

Substituting the value of V2

W = −P×nRTP-P×nRTP

W= - nRT

Substituting, n= 2.018

R = 2cal

T = 270 C = 300 K

W = - 2.018 ××2 ××300 = 1210.8 cal~ 1200 cal.

Option A is correct answer