Calculate the work done in pulling an object with a constant force Fas shown in figure, so that the block moves
with a constant velocity through a distance d. (given that the ground is rough with coefficient of friction u)
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Hey Dear,
You forgot to post the required image. But don't worry, I found the referred image on internet and will post here.
◆ Answer -
Work = μmgdcosθ / (cosθ + μsinθ)
◆ Explaination -
For the inclined motion of the block, normal reaction is given as
μN = Fcosθ
N = Fcosθ/μ
Now, weight of the block will balance normal reaction and vertical force.
W = N + Fsinθ
mg = Fcosθ/μ + Fsinθ
mg = F (cosθ/μ + sinθ)
F = mg / (cosθ/μ + sinθ)
F = μmg / (cosθ + μsinθ)
Now work done during this motion is -
Work = F.d
Work = Fdcosθ
Work = μmgdcosθ / (cosθ + μsinθ)
Best luck dear. Hope this helps you...
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